University of Wisconsin–Madison

test_mathjax

When $$\(a \ne 0\)$$, there are two solutions to \(ax^2 + bx + c = 0\) and they are
$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$

We study the addition of two {\scriptsize M \times N} rectangular random matrices with certain
invariant distributions in two limit regimes, where the parameter {\scriptsize \beta}

… we have `\(x_1 = 132\)` and `\(x_2 = 370\)` and so …

Using the Math Block, both independently and in line.

When (a≠0)(a \ne 0), there are two solutions to (ax2+bx+c=0)(ax^2 + bx + c = 0), and they are

x=−b±b2−4ac2a. x = {-b \pm \sqrt{b^2-4ac} \over 2a}.

We study the addition of two M×N{\scriptsize M \times N} rectangular random matrices with certain invariant distributions in two limit regimes, where the parameter beta{\scriptsize beta}

… we have (x1=132)(x_1 = 132) and (x2=370)(x_2 = 370) and so…